您当前的位置: 我在做android定位，我得到了json文件，希望只得到里面的城市名字，比如Mountain View，该如何做？
- Java code
{ "status": "OK", "results": [ { "types": [ "street_address" ], "formatted_address": "1600 Amphitheatre Pkwy, Mountain View, CA 94043, USA", "address_components": [ { "long_name": "1600", "short_name": "1600", "types": [ "street_number" ] }, { "long_name": "Amphitheatre Pkwy", "short_name": "Amphitheatre Pkwy", "types": [ "route" ] }, { "long_name": "Mountain View", "short_name": "Mountain View", "types": [ "locality", "political" ] }, { "long_name": "California", "short_name": "CA", "types": [ "administrative_area_level_1", "political" ] }, { "long_name": "United States", "short_name": "US", "types": [ "country", "political" ] }, { "long_name": "94043", "short_name": "94043", "types": [ "postal_code" ] } ], "geometry": { "location": { "lat": 37.4219720, "lng": -122.0841430 }, "location_type": "ROOFTOP", "viewport": { "southwest": { "lat": 37.4188244, "lng": -122.0872906 }, "northeast": { "lat": 37.4251196, "lng": -122.0809954 } } } } ] }
希望能提供代码 谢谢
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json可以转list，然后取出来就行了
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用json.jar
JSONOBject obj = JSONObject.from(str);
obj.getString("status");
......
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try {
JSONObject obj = new JSONObject("jsonstr");
JSONArray jsonArray = obj.getJSONArray("results");
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject jo = jsonArray.getJSONObject(i);
JSONArray jsonArray2 = jo.getJSONArray("address_components");
for (int j = 0; j < jsonArray2.length(); j++) {
JSONObject jobj = jsonArray2.getJSONObject(j);
String short_name = jobj.getString("short_name");
System.out.println(j+": "+short_name);
}
}
} catch (JSONException e) {
e.printStackTrace();
}
[]解析成JSONArray ，{}解析成JSONObject，楼主应该看得明白吧，另外推荐楼主在eclipse里安一个json编辑器插件这样好分析json字符串的结构
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既然只要取文件名，完全不用json API反而更快
直接截取字符串就可以完成
- Java code
String str=... //从Json文件读到的字符串
int index1 = str.indexOf("\"long_name\": \""）;
int index2 = str.indexOf("\"",index1+14);
String cityname = str.substring(index1,index2);
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用json.jar
JSONOBject obj = JSONObject.from(str);
obj.getString("status");